This is making me realize how rusty I am! If you are only concerned with the load on the spring and the thickness of the spring, then the maths simplifies to keeping the ratio of the load to the cube of the thickness constant. If you wanted to half the load, you half the cube of the thickness.
Fred
Reducing Winchester 1894 hammer spring power
Moderator: dromia
Forum rules
Should your post be in Grumpy Old Men? This area is for general shooting related posts only please.
Should your post be in Grumpy Old Men? This area is for general shooting related posts only please.
-
- Posts: 969
- Joined: Fri Dec 10, 2010 8:33 pm
- Home club or Range: stourport
- Location: Wolverhampton
- Contact:
Re: Reducing Winchester 1894 hammer spring power
I am not sure how clear the above is: lets look at an example:
If the spring was 1/8" thick and you want to half the effort to full cock, then cube the 1/8 giving 1/512. Divide that by two giving 1/1024. The cube root of 1/1024 is pretty close to 1/ 10 so reducing the thickness to a tenth of an inch and then polishing should do it.
Is this helping?
Fred
If the spring was 1/8" thick and you want to half the effort to full cock, then cube the 1/8 giving 1/512. Divide that by two giving 1/1024. The cube root of 1/1024 is pretty close to 1/ 10 so reducing the thickness to a tenth of an inch and then polishing should do it.
Is this helping?
Fred
Re: Reducing Winchester 1894 hammer spring power
Ah, I understand your last post Fred.
I think..... I may come back with some dimensions to confirm my thoughts on this!

I think..... I may come back with some dimensions to confirm my thoughts on this!
Who is online
Users browsing this forum: No registered users and 5 guests